In , P divides the side AB such that AP : PB = 1 : 2. Q is a point in AC such that . Find the ratio of the areas of and trapezium BPQC.

Untitled.jpg


We know


PQBC


1= AP


2 PB


In


A=A [Common]


APQ=B [Corresponding angle]


ABCAPQ


Area() =AP2


Area () AB2


ar ()___________ = 12/32


ar()+ar()


9ar()= ar()+ar()


9ar()- ar()=ar()


8ar()=ar()


ar() =


ar()


13