In , PQ is a line segment intersecting AB at P and AC at Q such that and PQ divides into two parts equal in area. Find .
We know
PQ∥BC
Area () =Area ()
Area () =Area ()- Area ()
2Area ()= Area () ………(i)
In
∠A=∠A [Common]
∠APQ=∠B [Corresponding angle]
ABCAPQ
Area() =AP2
Area () AB2
Area() =AP2
Area () AB2 [By using (I)]
1= AP2
2 AB2
=AP/AB
=
= -
=1-BP/AB
BP/AB=1-
BP/AB=