A ladder 17 m long reaches a window of a building 15 m above the ground. Find the distance of the foot of the ladder from the building.
In ⊿ ABC
AC2=AB2+BC2
172=152+BC2
289=225+BC2
BC2=289 – 225
BC2=64
BC=
BC=8 m
Distance of the foot of ladder is 8 m from the building.
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