In an isosceles triangle ABC, AB = AC = 25 cm, BC = 14 cm. Calculate the altitude from A on BC.
We have,
AB=AC=25cm
BC=14cm
In ⊿ ACD and ⊿ ABD
∠ADB=∠ADB=90
AB=AC=25cm
AD=AD (Common)
⊿ ABD≅∠ACD
∴BD=CD=7cm (By c.p.c.t)
In ⊿ACD
AB2=AD2+BD2
252=AD2+72
625=AD2+49
AD2=625-49
AD2=576
AD=
AD=24 cm