Using Pythagoras theorem determine the length of AD in terms of b and c shown in Fig 4.219.

In ABC


BC2=AB2+AC2


BC2=c2+b2


BC= ………………(i)


In ABC and In CBA


B= B (Common)


ADB=BAC=90°


ABD ~ CBA


AB/CB=AD/CA


c/ =AD/b


AD=bc/


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