Using Pythagoras theorem determine the length of AD in terms of b and c shown in Fig 4.219.
In ABC
BC2=AB2+AC2
BC2=c2+b2
BC= ………………(i)
In ABC and In CBA
∠B= ∠B (Common)
∠ADB=∠BAC=90°
∴ ABD ~ CBA
∴ AB/CB=AD/CA
c/ =AD/b
AD=bc/