In Fig. 4.221, and segment , show that

(i)


(ii)


In ADC

AC2=AD2+DC2


b2=h2+(a-x)2


b2=h2+a2-2ax+x2 ………… (i)


b2=h2+x2-2ax


b2=a2+ (h2+x2)-2ax (from equ.i)


b2=a2+c2-2ax [h2+x2=c2]


20