In Fig. 4.221, and segment , show that
(i)
(ii)
In ADC
AC2=AD2+DC2
b2=h2+(a-x)2
b2=h2+a2-2ax+x2 ………… (i)
b2=h2+x2-2ax
b2=a2+ (h2+x2)-2ax (from equ.i)
b2=a2+c2-2ax [h2+x2=c2]