Multiplying eq1 by 0.2 and eq2 by 0.3 and adding

⇒ 0.08x + 0.06y + 0.21x – 0.06y = 0.34 + 0.24

⇒ 0.29x = 0.58

⇒ x = 2

Substituting value of x in eq1, 0.8x + 0.3y = 1.7

⇒ y = 3