Solve the following systems of equations:


2x + 4y = 3 …(i)


4x + 2y = 3 …(ii)


Multiplying eq2 by 2 and subtracting from eq1


2x + 4y – 8x – 4y = 3 – 6


-6x = - 3


x = 1/2


Thus, 2 × 1/2 + 4y = 3 y = 1/2


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