Solve the following systems of equations:


where, x + y ≠ 0 and x - y ≠ 0



Dividing the two equations


⇒ (y –x )/(x + y) = 1/5


⇒ 5y – 5x = x + y


⇒ y = 3x/2


Thus,


⇒ 3x/5 = 6/5


⇒ x = 2


Thus, y = 3


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