Solve the following systems of equations:
Multiplying eq1 by 3 and subtracting from eq2
⇒ -11/(x + y) = -1
⇒ x + y = 11 ---------- (3)
Multiplying eq1 by 5 and eq2 by 2 and subtracting
⇒ 15/(x –y) = 3
⇒ x – y = 5 ------ (4)
(3) + (4)
⇒ 2x = 16
⇒ x = 8
Thus, y = 3