Multiplying eq1 by 3 and subtracting from eq2

⇒ 13/(x – y) = 13

⇒ x – y = 1 ------ (3)

Multiplying eq1 by 7 and eq2 by 2 and adding

⇒ 65/(x + y) = 13

⇒ x + y = 5 ------- (4)

Thus, 2x = 6

⇒ x = 3

Y = x – 1

⇒ y = 2