Solve the following systems of equations:
Multiply eq1 by 4 and eq2 by 3 and adding
⇒ 25/x = 125
⇒ x = 1/5
Thus, 20 + 3y = 14
⇒ y =- 2
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Solve the following systems of equations:
Multiply eq1 by 4 and eq2 by 3 and adding
⇒ 25/x = 125
⇒ x = 1/5
Thus, 20 + 3y = 14
⇒ y =- 2