Solve the following systems of equations:
Subtracting eq2 and eq3
⇒ x + 3y = 0
⇒ x = -3y
Substituting in eq1
⇒ -3y – y + z = 4
⇒ z = 4 + 4y
Substituting in eq2
⇒ -3y – 2y + 12 + 12y = 1
⇒ 7y = -11
⇒ y = -11/7
Thus, x = 33/7
And z = 4 – 44/7 = - 16/7