Solve the following systems of equations:




Multiplying eq2 by 2 and adding to eq1


2/(3x + y) = 3/4 - 2/8


3x + y = 4 ---- (3)


Multiplying eq2 by 2 and subtracting from eq1


2/(3x – y ) = 1


3x – y = 2 ----- (4)


Adding (3) and (4)


6x = 6


x = 1


Thus, y = 3 – 2 = 1


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