Find the value of k for which the following system of equations has a unique solution:
Multiplying eq2 by 2 and subtracting from eq1
⇒ (k – 4)y + 6 = 0
⇒ y = 6/(4 – k)
Thus, for k ≠ 4 it has a unique solution
6
Find the value of k for which the following system of equations has a unique solution:
Multiplying eq2 by 2 and subtracting from eq1
⇒ (k – 4)y + 6 = 0
⇒ y = 6/(4 – k)
Thus, for k ≠ 4 it has a unique solution