Ten years later, A will be twice as old as B and five years ago, A was three times as old as B. What are the present ages of A and B?

Let the present ages of A and B be ‘a’ and ‘b’ respectively.


Given, ten years later, A will be twice as old as B and five years ago, A was three times as old as B


a + 10 = 2(b + 10)


a = 2b + 10 ------- (1)


Also, a – 5 = 3(b – 5)


a = 3b – 10 -------- (2)


Equating eq2 and eq1


2b + 10 = 3b – 10


b = 20


Thus, a = 2b + 10 = 50


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