Let the father’s age be ‘a’ and son’s age be ‘b’

Given, present age of a father is three years more than three times the age of the son.

⇒ a = 3b + 3 ---------- (1)

Also, three years hence father’s age will be 10 years more than twice the age of the son.

⇒ a + 3 = 2(b + 3) + 10

⇒ a = 2b + 13 --------- (2)

Equating (1) and (2), we get

3b + 3 = 2b + 13

⇒ b = 10 years

Father’s age (a) = 3 × 10 + 3 = 33