Let the present age of father be ‘a’ and present age of son be b.

Given, two years ago, a father was five times as old as his son. Two years later, his age will be 8 more than three times the age of the son.

⇒ a – 2 = 5(b – 2)

⇒ a = 5b – 8 ------ (1)

Also, a + 2 = 3(b + 2) + 8

⇒ a = 3b + 12 ----- (2)

Equating (1) and (2)

⇒ 5b – 8 = 3b + 12

⇒ b = 10

Thus father’s age = 50 – 8 = 42