A train covered a certain distance at a uniform speed. If the train could have been 10 km/hr. faster, it would have taken 2 hours less than the scheduled time. And, if the train were slower by 10 km/hr, it would have taken 3 hours more than the scheduled time. Find the distance covered by train.

Let the speed of train be ‘s’, scheduled time be ‘t’ and distance be ‘d’.


Speed = distance/time


Given, covered a certain distance at a uniform speed. If the train could have been 10 km/hr. faster, it would have taken 2 hours less than the scheduled time. And, if the train were slower by 10 km/hr, it would have taken 3 hours more than the scheduled time.


d = st ------- (1)


d = (s + 10)(t – 2) ------ (2)


d = (s – 10)(t + 3) ------ (3)


Solving the above three equation we get, d = 600km, s = 50 km/hr and t = 12 hours


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