The following table shows the marks scored by 140 students in an examination of a certain paper:
Marks: | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
Number of students: | 20 | 24 | 40 | 36 | 20 |
Calculate the average marks by using all the three methods: direct method, assumed mean deviation and shortcut method.
From Direct method:
Class interval | Mid value (xi) | fi | fixi |
0-10 | 5 | 20 | 100 |
10-20 | 15 | 24 | 360 |
20-30 | 25 | 40 | 1000 |
30-40 | 35 | 36 | 1260 |
40-50 | 45 | 20 | 900 |
N = 140 | ∑fixi = 3620 |
Mean =
= = 25.857
Assumed mean method: let assumed mean (A) = 25
Mean = A +
Class interval | Mid value (xi) | ui = xi – A | fi | fiui |
0-10 | 5 | -20 | 20 | -400 |
10-20 | 15 | -10 | 24 | -240 |
20-30 | 25 | 0 | 40 | 0 |
30-40 | 35 | 10 | 36 | 360 |
40-50 | 45 | 20 | 20 | 400 |
N = 140 | ∑fiui = 120 |
Mean = A +
= 25 + = 25 + 0.857
= 25.857
Step deviation method: Let the assumed mean (A) = 25
Class interval | Mid value (xi) | di = xi – A = xi - 25 | ui = | Frequency (fi) | fiui |
0-10 | 5 | -20 | -2 | 20 | -40 |
10-20 | 15 | -10 | -1 | 24 | -24 |
20-30 | 25 | 0 | 0 | 40 | 0 |
30-40 | 35 | 10 | 1 | 36 | 36 |
40-50 | 45 | 20 | 2 | 20 | 40 |
N = 140 | ∑fiui = 12 |
Mean = A + * h
= 25 + * 10
= 25 + 0.857 = 25.857