If the median of the following frequency distribution is 28.5 find the missing frequencies:
Class interval: | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | Total |
Total Frequency: | 5 | 20 | 15 | 5 | 60 |
Class interval | Frequency | Cumulative frequency |
0-10 | 5 | 5 |
10-20 | f1 | 5 + f1 (f) |
20-30 | 20 (f) | 25 + f1 |
30-40 | 15 | 40 + f1 |
40-50 | f2 | 40 + f1 + f2 |
50-60 | 5 | 45 + f1 + f2 |
N = 60 |
Given, Median = 28.5
Then, median class is 20-30
l = 20, f = 20, F = 5 + f1, h = 10
Median = l +
28.5 = 20 + * 10
28.5 – 20 = * 10
8.5 =
f1 = 25 – 17
f1 = 8
Given, sum of frequencies = 60
= 5 + f1 + 20 + 15 + f2 + 5 = 60
= 5 + 8 + 20 + 15 + f2 + 5 = 60
f2 = 7
Therefore, f1 = 8 and f2 = 7