Compute the median for each of the following data


(i) Marks



No. of students



(ii) Marks



No. of students



Less than 10



0



More than150



0



Less than 30



10



More than140



12



Less than 50



25



More than130



27



Less than 70



43



More than120



60



Less than 90



65



More than110



105



Less than 110



87



More than100



124



Less than 130



96



More than90



141



Less than 150



100



More than80



150


(i)


Marks



No. of students



Class interval



Frequency



Cumulative frequency



Less than 10



0



0-10



0



0



Less than 30



10



10-30



10



10



Less than 50



25



30-50



15



25



Less than 70



43



50-70



18



43 (F)



Less than 90



65



70-90



22 (f)



65



Less than 110



87



90-110



22



87



Less than 130



96



110-130



9



96



Less than 150



100



130-150



4



100






N = 100




We have, N = 100


= = 50


The cumulative frequency just greater than is 65 then median Class 70-90, such that:


l = 70, f = 22, F = 43, h = 20


Median = l + * h


= 70 + * 20


= 70 +


= 70 + 6.36 = 76.36


(ii)


Marks



No. of students



Class interval



Frequency



Cumulative frequency



More than 80f



150



80-90



9



9



More than 90



141



90-100



17



16



More than 100



124



100-110



19



45 (F)



More than 110



105



110-120



45 (f)



90



More than 120



60



120-130



33



123



More than 130



27



130-140



15



138



More than 140



12



140-150



12



150



More than 150



0



150-160



0



150






N = 150




We have, N = 150


= = 7


The cumulative frequency is just more than is 90 then, the Median Class is 110-120 such that:


l = 110, f = 45, F = 45, h = 10


Median = l + * h


= 110 + * 10


= 110 +


= 110 + 6.67


= 116.67


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