100 surnames were randomly picked up from a local telephone directly and the frequency distribution of the number of letters in the English alphabets in the surnames was obtained as follows:
Numbers of letters: | 1-4 | 4-7 | 7-10 | 10-13 | 13-16 | 16-19 |
Number surnames: | 6 | 30 | 40 | 16 | 4 | 4 |
Determine the median number of letters in the surnames. Find the mean number of letters in the surnames. Also, find the modal size of the surnames.
Class interval | Mid value (x) | Frequency (f) | fx | Cumulative frequency |
1-4 | 2.5 | 6 | 15 | 6 |
4-7 | 5.5 | 30 | 165 | 36 |
7-10 | 8.5 | 40 | 340 | 76 |
10-13 | 11.5 | 16 | 185 | 92 |
13-16 | 14.5 | 4 | 58 | 96 |
16-19 | 17.5 | 4 | 70 | 100 |
Total | N=100 |
Mean= =
We have, N= 100,
N/2 = 50
Hence, median class =7-10, such that
l=7, f’=40, f=36, h=3
Median = l +
Here, we may observe that maximum class frequency is 40 belonging to the class interval 7-10
So, modal class= 7-10
Lower limit, l= 7
f0=30, f2=16, f=40,h = 3
=