Express the following numbers in standard form:

(i) 6020000000000000

(ii) 0.00000000000942

(iii) 0.00000000085

(iv)

(v)

(vi) 0.00072984

(vii) 0.000437

(viii)

(i) 6020000000000000

To write in the standard form, count the number of digits leaving one digit from the left. The total number of digits so obtained becomes power of 10. Decimal comes after first left digit.

In this question total number of digits leaving one digit from left are 15.

Therefore the standard form is: _{6.02× 10}^{15}

(ii) 0.00000000000942

To write in the standard form, count the number of digits leaving one digit from the left. The total number of digits so obtained becomes power of 10. Decimal comes after first left digit.

If the number has all the digits to the right of the decimal then powers will be negative. In this question total number of digits after decimal are 12.

Therefore the standard form is: _{9.42× 10}^{–12}

(iii) 0.00000000085

To write in the standard form, count the number of digits leaving one digit from the left. The total number of digits so obtained becomes power of 10. Decimal comes after first left digit.

If the number has all the digits to the right of the decimal then powers will be negative. In this question total number of digits after decimal are 12.

Therefore the standard form is: _{8.5× 10}^{–10}

(iv)

In this question total number of digits are 2.

Therefore the standard form is: _{8.46× 10}^{9}

In this question total number of digits are 3.

Therefore the standard form is: _{8.46× 10}^{–1}

If the number has all the digits to the right of the decimal then powers will be negative. In this question total number of digits after decimal are 4.

Therefore the standard form is: _{7.2984× 10}^{–4}

If the number has all the digits to the right of the decimal then powers will be negative. In this question total number of digits after decimal are 4.

Therefore the standard form is: 4.37

To write in the standard form, Count the number of zeros of the divisor. This number of zeros becomes negative power of 10.

Therefore the standard form is: _{4× 10}^{–5}

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