If x+y = 4 and xy=2, find the value of x2+y2

Given that,


x + y = 4 and xy=2


We take the equation: x + y = 4 and on squaring both sides, we get


(x + y)2 = 42


x2 + y2 + 2xy = 16


x2 + y2 + 2 (2) = 16  (Because xy=2 is given)


x2 + y2 + 4  = 16


x2 + y2 = 16 – 4


x2 + y2 =12


Therefore, the value of x2 + y2 is 12

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