Resolve each of the following quadratic trinomials into factors:
= - 2x2 + 7x – 6
Here, coefficient of x2 = -2, coefficient of x = 7and constant term = -6
We shall now split up the coefficient of x i.e., 7 into two parts whose sum is 7 and product is -2 * -6 = 12
Clearly,
4 + 3 = 7 and,
4 * 3 = 12
So, we write middle term 7x as 4x + 3x
Thus, we have
-2x2 + 7x – 6 = -2x2 + 4x + 3x – 6
= -2x (x – 2) + 3 (x – 2)
= (x – 2) (3 – 2x)