Resolve each of the following quadratic trinomials into factors:

7x – 6x2 + 20 = - 6x2 + 7x + 20

Here, coefficient of x2 = -6, coefficient of x = 7and constant term = 20


We shall now split up the coefficient of x i.e., 7 into two parts whose sum is 7 and product is -6 * 20 = - 120


Clearly,


15 - 8 = 7 and,


15 (-8) = - 120


So, we write middle term 7x as 15x - 8x


Thus, we have


-6x2 + 7x + 20 = -6x2 + 15x - 8x + 20


= -3x (2x – 5) - 4 (2x – 5)


= - (3x + 4) (2x - 5)


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