Resolve each of the following quadratic trinomials into factors:

3x2 + 22x + 35

Here, coefficient of x2 = 3, coefficient of x = 22 and constant term = 35


We shall now split up the coefficient of x i.e., 22 into two parts whose sum is 22 and product is 3 * 35 = 105


So, we write middle term 22x as 15x + 7x


Thus, we have


3x2 + 22x + 35= 3x2 + 15x + 7x + 35


= 3x (x + 5) + 7 (x + 5)


= (3x + 7) (x+ 5)


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