Resolve each of the following quadratic trinomials into factors:

Here, coefficient of x2 = 15, coefficient of x = -16yz and constant term = - 15y2z2

We shall now split up the coefficient of middle term i.e., -16yz into two parts whose sum is -16yz and product is 15 (-15y2z2) = - 225y2z2


Clearly,


-25yz + 9yz = -16yz and,


(-25yz) (9yz) = - 225y2z2


So, we replace middle term -16xyz = -25yz – 9yz


Thus, we have


15x2 -16xyz- 15y2z2 = 15x2 - 25yz + 9yz - 15y2z2


= 5x (3x – 5yz) + 3yz (3x – 5yz)


= (5x + 3yz) (3x - 5yz)


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