Write the cubes of 5 natural numbers which are multiples of 3 and verify the followings:
“The cube of a natural number which is a multiple of 3 is a multiple of 27’
First 5 natural numbers which are multiple of 3 are = 3 , 6 , 9 , 12 , 15
Now, cube of them are,
= 33 = 3 × 3 × 3 = 27
= 63 = 6 × 6 × 6 = 216
= 93 = 9 × 9 × 9 = 729
= 123 = 12 × 12 × 12 = 1728
= 153 = 15 × 15 × 15 = 3375
We find that all the cubes are divisible by 27,
Therefore, “The cube of a natural number which is a multiple of 3 is a multiple of 27’