Find the cubes of the following numbers by column method:
(i) 35
(ii) 56
(iii) 72
(i) 35
we have , a = 3 and b = 5
Column I | Column II | Column III | Column IV |
+15 | +23 | +12 | |
15 | 23 | ||
42 | 8 | 7 | 5 |
Thus cube of 35 is 42875.
(ii) 56
we have , a = 5 and b = 6
Column I | Column II | Column III | Column IV |
+50 | +56 | +21 | 21 |
50 | 56 | ||
175 | 6 | 1 | 6 |
Thus cube of 56 is 175616.
(iii) 72
we have , a = 7 and b = 2
Column I | Column II | Column III | Column IV |
+30 | +8 | +0 | |
30 | 8 | ||
373 | 2 | 4 | 8 |
Thus cube of 72 is 373248.