Find the cubes of the following numbers by column method:

(i) 35


(ii) 56


(iii) 72

(i) 35


we have , a = 3 and b = 5


Column I




Column II




Column III




Column IV












+15



+23



+12



12





15



23




42



8



7



5



Thus cube of 35 is 42875.


(ii) 56


we have , a = 5 and b = 6


Column I




Column II




Column III




Column IV












+50



+56



+21



21





50



56




175



6



1



6



Thus cube of 56 is 175616.


(iii) 72


we have , a = 7 and b = 2


Column I




Column II




Column III




Column IV












+30



+8



+0







30



8




373



2



4



8



Thus cube of 72 is 373248.


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