For each of the non-pefectcubbes in Q. No 20 find the smallest number by which it must be
(a) Multiplied so that the product is a perfect cube.
(b) Divided so that the quotient is a perfect cube.
Only non-perfect cube in previous question was = 243
(a) Multiplied so that the product is a perfect cube.
Prime factors of 243 = 3 × 3 × 3 × 3 × 3 = 33 × 32
Hence, to make it a perfect cube we should multiply it by 3.
(b) Divided so that the quotient is a perfect cube.
Prime factors of 243 = 3 × 3 × 3 × 3 × 3 = 33 × 32
Hence, to make it a perfect cube we have to divide it by 9.