Using the method of successive subtraction examine whether or not the following numbers are perfect cubes:

(i) 130


(ii) 345


(iii) 792


(iv) 1331

(i) 130


Applying subtraction method, We have,


130 – 1 = 129


129 – 7 = 122


122 – 19 = 103


103 – 37 = 66


66 – 61 = 5


Next number to be subtracted is 91, which is greter than 5


Hence, 130 is not a perfect cube.


(ii) 345


Applying subtraction method, We have,


345 – 1 = 344


344 – 7 = 337


337 – 19 = 318


318 – 37 = 281


281 – 61 = 220


220 – 91 = 129


129 – 127 = 2


Next number to be subtracted is 169, which is greter than 2


Hence, 345 is not a perfect cube


(iii) 792


Applying subtraction method, We have,


792 – 1 = 791


791 – 7 = 784


784 – 19 = 765


765 – 37 = 728


728 – 61 = 667


667 – 91 = 576


576 – 127 = 449


449 – 169 = 280


280 – 217 = 63


Next number to be subtracted is 271, which is greter than 63


Hence, 792 is not a perfect cube


(iv) 1331


Applying subtraction method, We have,


1331 – 1 = 1330


1330 – 7 = 1323


1323 – 19 = 1304


1304 – 37 = 1267


1267 – 61 = 1206


1206 – 91 = 1115


1115 – 127 = 988


988 – 169 = 819


819 – 217 = 602


602 – 271 = 331


331 – 331 = 0


Subtraction is performed 11 times.


Hence, 1331 is a perfect cube


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