In Fig. 16.21, the bisectors of ∠A and ∠B meet at a point P. If ∠C =100° and ∠D = 50°, find the measure of ∠APB.
Sum of angles of a quadrilateral is 360°
In the quadrilateral ABCD
∠D = 50°, ∠C = 100°,
∠A + ∠B + ∠C + ∠D = 360°
∠A + ∠B + 100° + 50° =
∠A + ∠B =
∠A + ∠B = 210° ……….(i)
Now in Δ APB
[Sum of angles of a triangle is 180°]
…….(ii)
On substituting value of ∠A + ∠B = 210 from equation (i) in equation (ii)