In a quadrilateral ABCD, CO and DO are the bisectors of ∠C and ∠D respectively. Prove that ∠COD = (∠A +∠B).
Sum of angles of a quadrilateral is 360°
In the quadrilateral ABCD
∠A + ∠B + ∠C + ∠D = 360°
∠A + ∠B =
…….(i)
Now in Δ DOC
[Sum of angles of a triangle is 180°]
……….(ii)
From above equations (i) and (ii) RHS is equal therefore LHS will also be equal.
Therefore