In a quadrilateral ABCD, CO and DO are the bisectors of C and D respectively. Prove that COD = (A +B).

Sum of angles of a quadrilateral is 360°


In the quadrilateral ABCD



A + B + C + D = 360°


A + B =



…….(i)


Now in Δ DOC


[Sum of angles of a triangle is 180°]



……….(ii)


From above equations (i) and (ii) RHS is equal therefore LHS will also be equal.


Therefore


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