In a convex hexagon, prove that the sum of all interior angle is equal to twice the sum of its exterior angles formed by producing the sides in the same order.
The sum of interior angles of a polygon = (n – 2) × 180°
The sum of interior angles of a hexagon = (6 – 2) × 180° = 4 × 180° = 720°
The Sum of exterior angle of a plygon is 360°
Therefoe sum of interior angles of a hexagon = twice the sum of interior angles.