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The length of a side of a square field is 4 m. What will be the altitude of the rhombus, if the area of the rhombus is equal to the square field and one of its diagonal is 2 m?
Length of square = 4 m
Area of square = side2
Area of square = 4 × 4 = 16 m2
Area of square = area of rhombus
Area of rhombus = 16 m2
Area of rhombus =
16 =
Other diagonal of rhombus = 16 m
In ΔAOB
Using pythagorous theorem:
AB2 = OA2 + OB2
AB2 = 82 + 12
AB2 = 65
AB =
Rhombus is a parallelogram, area of parallelogram = base× altitude
Area of parallelogram = AB × DE
Area of parallelogram = × DE
DE =
Altitude of Rhombus = cm