The length of a side of a square field is 4 m. What will be the altitude of the rhombus, if the area of the rhombus is equal to the square field and one of its diagonal is 2 m?

Length of square = 4 m

Area of square = side^{2}

Area of square = 4 × 4 = 16 m^{2}

Area of square = area of rhombus

Area of rhombus = 16 m^{2}

Area of rhombus =

16 =

Other diagonal of rhombus = 16 m

In ΔAOB

Using pythagorous theorem:

AB^{2} = OA^{2} + OB^{2}

AB^{2} = 8^{2} + 1^{2}

AB^{2} = 65

AB =

Rhombus is a parallelogram, area of parallelogram = base× altitude

Area of parallelogram = AB × DE

Area of parallelogram = × DE

DE =

Altitude of Rhombus = cm

15