The length of a side of a square field is 4 m. What will be the altitude of the rhombus, if the area of the rhombus is equal to the square field and one of its diagonal is 2 m?

Length of square = 4 m


Area of square = side2


Area of square = 4 × 4 = 16 m2


Area of square = area of rhombus


Area of rhombus = 16 m2


Area of rhombus =


16 =


Other diagonal of rhombus = 16 m


In ΔAOB



Using pythagorous theorem:


AB2 = OA2 + OB2


AB2 = 82 + 12


AB2 = 65


AB =


Rhombus is a parallelogram, area of parallelogram = base× altitude


Area of parallelogram = AB × DE


Area of parallelogram = × DE


DE =


Altitude of Rhombus = cm


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