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In Fig. 20.38, a parallelogram is drawn in a trapezium, the area of the parallelogram is 80 cm2, find the area of the trapezium.
In ΔCEF
CE = 10 cm and EF = 6cm
Using pythagorous theorem:
CE2 = CF2 + EF2
CF2 = CE2 - EF2
CF2 = 102 - 62
CF2 = 100-36
CF2 = 64
CF = 8 cm
Area of parallelogram = 80 cm2
Area of trapezium = area of parallelogram AECD + area of area of triangle CEF
Area of trapezium =
Area of trapezium =
Area of trapezium = 80 + 48 = 128 cm2