Find the area of the pentagon shown in fig. 20.48, if AD = 10 cm, AG = 8 cm, AH = 6 cm, AF = 5 cm, BF = 5 cm, CG = 7 cm and EH = 3 cm.
GH = AG – AH = 8 – 6 = 2 cm
HF = AH – AF = 6 – 5 = 1 cm
GD = AD – AG = 10 – 8 = 2 cm
Area of given figure = area of triangle AFB + area of trapezium BCGF + area of triangle CGD + area of triangle AHE + area of triangle EGD
Area of right angled triangle = 
Area of trapezium = 
Area of given pentagon = 
Area of given pentagon = 
Area of given pentagon = 
= 52.5 cm2
Therefore area of given pentagon is 70 cm2
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