Find the area of the following polygon, if *AL* = 10 cm, *AM* = 20 cm, *AN* = 50 cm. *AO* = 60 cm and *AD* = 90 cm.

AL = 10 cm; AM = 20 cm; AN = 50 cm; AO = 60 cm; AD = 90 cm given

LM = AM – AL = 20 – 10 = 10 cm

MN = AN – AM = 50 – 20 = 30 cm

OD = AD – AO = 90 – 60 = 30 cm

ON = AO – AN = 60 – 50 = 10 cm

DN = OD + ON = 30 + 10 = 40 cm

OM = MN + ON = 30 + 10 = 40 cm

LN = LM + MN = 10 + 30 = 40 cm

Area of given figure = area of triangle AMF + area of trapezium FMNE + area of triangle END + area of triangle ALB + area of trapezium LBCN + area of triangle DNC

Area of right angled triangle =

Area of trapezium =

Area of given hexagon =

Area of given hexagon =

Area of given hexagon = = 5050 cm^{2}

Therefore area of given hexagon is 5050 cm^{2}

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