Book: RD Sharma - Mathematics
Chapter: 20. Mensuration-I (Area of a Trapezium and a Polygon)
Subject: Maths - Class 8th
Q. No. 4 of Exercise 20.3
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Find the area of the following polygon, if AL = 10 cm, AM = 20 cm, AN = 50 cm. AO = 60 cm and AD = 90 cm.
AL = 10 cm; AM = 20 cm; AN = 50 cm; AO = 60 cm; AD = 90 cm given
LM = AM – AL = 20 – 10 = 10 cm
MN = AN – AM = 50 – 20 = 30 cm
OD = AD – AO = 90 – 60 = 30 cm
ON = AO – AN = 60 – 50 = 10 cm
DN = OD + ON = 30 + 10 = 40 cm
OM = MN + ON = 30 + 10 = 40 cm
LN = LM + MN = 10 + 30 = 40 cm
Area of given figure = area of triangle AMF + area of trapezium FMNE + area of triangle END + area of triangle ALB + area of trapezium LBCN + area of triangle DNC
Area of right angled triangle = 
Area of trapezium = 
Area of given hexagon = 
Area of given hexagon = 
Area of given hexagon = 
= 5050 cm2
Therefore area of given hexagon is 5050 cm2
