RD Sharma - Mathematics

Book: RD Sharma - Mathematics

Chapter: 20. Mensuration-I (Area of a Trapezium and a Polygon)

Subject: Maths - Class 8th

Q. No. 5 of Exercise 20.3

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5

Find the area of the following regular hexagon.

NQ = 23 cm given


ND + QC = 23 -13 = 10


ND = QC = 5 cm


OM = 24 cm


Area of given hexagon = 2 times area of triangle MNO + area of rectangle MOPR


Area of right angled triangle =


Area of rectangle = length × breadth


Area of regular hexagon =


Area of given hexagon = = 432 cm2


Therefore area of given hexagon is 432 cm2


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