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Find the area of the following regular hexagon.
NQ = 23 cm given
ND + QC = 23 -13 = 10
ND = QC = 5 cm
OM = 24 cm
Area of given hexagon = 2 times area of triangle MNO + area of rectangle MOPR
Area of right angled triangle =
Area of rectangle = length × breadth
Area of regular hexagon =
Area of given hexagon = = 432 cm2
Therefore area of given hexagon is 432 cm2