The total surface area of a hollow cylinder which is open from both sides if 4620 sq. cm, area of base ring is 115.5 sq. cm. and height 7 cm. Find the thickness of the cylinder.
Given,
Total surface area of hollow cylinder = 4620 cm2
Area of base ring = 115.5 cm2
Height of cylinder = 7 cm
Let outer radius = R cm , inner radius = r cm
So,
Area of hollow cylinder = 
=2
Area of base = 
∴ 
= 
= 
= 
=
Thickness of cylinder = 
16