In each of the following, determine whether the given values are solutions of the given equation or not:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
(vii)
We will have to check for each value and see whether it satisfies the equation.
(i)
For x = 2,
22 – 3 × 2 + 2 = 0
⇒ 0 = 0
Thus, x = 2 is a solution.
For, x = 1
12 – 3 × 1 + 2 = 0
⇒ 0 = 0
Thus, x = 1 is a solution.
(ii)
For x = 0,
⇒ 0 + 0 + 1 = 0
⇒ 1 = 0 which is not true thus x = 0 is not a solution
For x = 1,
⇒ 1 + 1 + 1 = 0
⇒ 3 = 0 which is not true thus x = 1 is not a solution
(iii)
For x= √3
⇒ 3 – 3√3 × √3 + 6 = 0
⇒ 3 – 9 + 6 = 0
⇒ 0 = 0
Thus, x = √3 is a solution
For x = -2√3
⇒ (-2√3)2 – 3√3 × -2√3 + 6 = 0
⇒ 4 × 3 + 18 + 6 = 0
⇒ 36 = 0 which is not true, thus x = -2√3 is not a solution
(iv)
For x = 5/6
⇒ 61 = 65 which is not true, thus x = 5/6 is not a solution
For x = 4/3
⇒ 25/12 = 13/6
⇒ 25 = 26 which is not true, thus x = 4/3 is not a solution
(v)
For x = 2,
⇒ 2 × 4 – 2 + 9 = 4 + 4 × 2 + 3
⇒ 15 = 15, thus x = 2 is a solution.
For x = 3
⇒ 2 × 9 – 3 + 9 = 9 + 4 × 3 + 3
⇒ 24 = 24, thus x = 3 is also a solution
(vi)
For x = -√2,
⇒ 2 - √2 × -√2 – 4 = 0
⇒ 2 + 2 – 4 = 0
⇒ 0 = 0
Thus, x = -√2 is a solution
For x = -2√2
⇒ 4 × 2 - √2 × -2√2 – 4 = 0
⇒ 8 + 8 – 4 = 0
⇒ 12 = 0 which is not true, thus x = -2√2 is not a solution
(vii)
For, x = a/b
⇒ a4/b2 – 3a2 + 2b2 = 0 which is not true, thus x = a/b is not a solution
For x = b/a
⇒ b2 – 3b2 + 2b2 = 0
⇒ 0 = 0 , thus x = b/a is a solution