Solve the following quadratic equations by factorization:

In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.



√3x2 – 3√2x + √2x – 2√3 = 0


√3x(x - √6) + √2(x - √6) = 0


(√3x + √2)(x - √6) = 0


x = √6, -√(2/3)


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