In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.

⇒ 6((x + 1)² - (x – 1)²) = 5(x² – 1)

⇒ 6 × 4x = 5x² – 5

⇒ 5x² – 24x – 5 = 0

⇒ 5x² – 25x + x – 5 = 0

⇒ 5x(x – 5) + 1(x-5) = 0

⇒ (5x + 1)(x – 5) = 0

⇒ x = 5, -1/5