Solve the following quadratic equations by factorization:
In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.
Let (x – a)/(x – b) = y and a/b = c
⇒ cy2 + c = c2y + y
⇒ cy2 – c2y –y + c = 0
⇒ cy(y – c) – 1(y – c) = 0
⇒ (cy – 1)(y – c) = 0
⇒ y = 1/c, c
⇒ ax – a2 = bx – b2
⇒ x(a – b) = a2 – b2
⇒ x = a + b
Also, bx – ab = ax – ab
⇒ (b – a)x = 0
⇒ x = 0