Solve the following quadratic equations by factorization:
In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.
⇒ (ax – ab + bx – ab)(x – c) = 2c(x – a)(x – b)
⇒ ((a + b)x – 2ab)(x – c) = 2cx2 – 2c(a + b)x + 2abc
⇒ (a + b)x2 – (a + b)cx – 2abx + 2abc = 2cx2 – 2(a + b)cx +2abc
⇒ (a + b – 2c)x2 + ((a + b)c – 2ab)x = 0
⇒ x = 0,