Solve the following quadratic equations by factorization:
In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.
⇒ (a + b)2x2 - (a2 + b2 + 2ab – a2 – b2 + 2ab)x – (a – b)2 = 0
⇒ (a + b)2x2 – (a + b)2x + (a – b)2x – (a – b)2 = 0
⇒ (a + b)2x(x - 1) + (a – b)2(x – 1) = 0
⇒ ((a + b)2x + (a – b)2)(x – 1) = 0
⇒ x = 1, 
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