Solve the following quadratic equations by factorization:

In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.




2ab(2x – 2a – b – 2x) = (2a + b)2x(2a + b + 2x)


2ab(-2a – b)= 2(2a+ b)(2ax + bx + 2x2)


-ab = 2ax + bx + 2x2


2x2 + 2ax + bx + ab = 0


2x(x + a) + b(x + a) = 0


(2x + b)(x + a) = 0


x = -a, -b/2


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