Solve the following quadratic equations by factorization:
In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.
⇒ 2ab(2x – 2a – b – 2x) = (2a + b)2x(2a + b + 2x)
⇒ 2ab(-2a – b)= 2(2a+ b)(2ax + bx + 2x2)
⇒ -ab = 2ax + bx + 2x2
⇒ 2x2 + 2ax + bx + ab = 0
⇒ 2x(x + a) + b(x + a) = 0
⇒ (2x + b)(x + a) = 0
⇒ x = -a, -b/2