If the roots of the equation are equal, prove that either a = 0 or a3 + b3 + c3 = 3abc.

For a quadratic equation, ax2 + bx + c = 0,


D = b2 – 4ac


If D = 0, roots are equal


Given, roots of are equal.


D = 0


4(a2 – bc)2 – 4(c2 – ab)(b2 – ac) = 0


a4 + b2c2 – 2a2bc – b2c2 – a2bc + ab3 + ac3 = 0


a(a3 + b3 + c3 – 3abc) = 0


a = 0 or a3 + b3 + c3 = 3abc


11